Attn Programmers I Will Pay 25USD To Fix One Line Of Code (NEEDED ASAP) - GoFuckYourself.com

SeanLEE · 11-02-2015, 08:22 AM

I need help with a site. I will pay 25 usd to the first person who can help me with 1 line of code.

Here is a snippet of the code:

Code:

 <?php foreach ($query->result() as $row):?>
<!DOCTYPE html>
<html lang="en">
<head prefix="og: http://ogp.me/ns# fb: http://ogp.me/ns/fb# website: http://ogp.me/ns/website#">
<head>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
    <meta name="viewport" content="width=device-width, initial-scale=1.0, maximum-scale=3.0, user-scalable=yes" />
     <title><?php echo $row->titulo; ?> - <?php echo $ciudad; ?><?php echo $this->codigo; ?> - <?php echo $this->categoria_model->ObtenerNombreCategoria($row->categoria);?> - <?php echo  $this->website; ?>
</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<meta name="keywords" content="<?php echo dinv_extracto(strip_tags($row->descripcion),10); ?>">
<meta name="description" content="<?php echo dinv_extracto(strip_tags($row->descripcion),40); ?>">
<meta property="og:image" content="<?php echo base_url(); ?>upload/gallery.php?imagen=<?php echo $fila['imagen1']; ?>"/>

The line:
<meta property="og:image" content="<?php echo base_url(); ?>upload/gallery.php?imagen=<?php echo $fila['imagen1']; ?>"/>

when I run it through facebook debugger tool it only sees:
<meta property="og:image" content="http://www.hiphopfind.com/upload/gallery.php?imagen=">

It cant pick up the <?php echo $fila['imagen1']

Can someone tell me what line of code I can place before this for it to be able to read this?

I will send 25usd to first person who can help me with this issue.

Thanks In advance!

If you need contact me on skype to fix go: Skype: seanleebiz

2MuchMark · 11-02-2015, 08:28 AM

Try changing

<meta property="og:image" content="<?php echo base_url(); ?>upload/gallery.php?imagen=<?php echo $fila['imagen1']; ?>

to

<meta property="og:image" content="<?php echo base_url(); ?>upload/gallery.php"?imagen="<?php echo $fila['imagen1']; ?>"

SeanLEE · 11-02-2015, 08:30 AM

Quote:

Originally Posted by **********

Try changing

<meta property="og:image" content="<?php echo base_url(); ?>upload/gallery.php?imagen=<?php echo $fila['imagen1']; ?>

to

<meta property="og:image" content="<?php echo base_url(); ?>upload/gallery.php"?imagen="<?php echo $fila['imagen1']; ?>"

It looks like you wrote the same line? I understrand what your saying..but the problem is facebook cant read the <?php echo $fila['imagen1']

sarettah · 11-02-2015, 08:34 AM

There really is not enough code there to be sure what the issue is but my guess would be that instead of echo $fila['imagen1']; You should have echo $row->imagen1; or some such. (I say thatbecause fila means row. It looks like someone modified a script and maybe missed changing up a var to me.

Without seeing what is in the database and what vars are coming from where all anyone can do is guess.

.

sarettah · 11-02-2015, 08:35 AM

Quote:

Originally Posted by SeanLEE

It looks like you wrote the same line? I understrand what your saying..but the problem is facebook cant read the <?php echo $fila['imagen1']

I do believe that facebook is failing to see it because $fila[] does not exist as such. Again, just a guess.

SeanLEE · 11-02-2015, 08:42 AM

Quote:

Originally Posted by sarettah

I do believe that facebook is failing to see it because $fila[] does not exist as such. Again, just a guess.

Yes I didnt want to put the whole code..the file exist...

here is another snippet of code:

<?php if ($numero_imagenes>0) { ?>

<?php

foreach ($data->result_array() as $fila)
{

?>

<?php if (!empty($fila['imagen1']))

{

?>
<div class="d_al"><a href="<?php echo base_url()."upload/gallery.php?imagen=".$fila['imagen1']; ?>" rel="lightbox[gallery]" title="<?php echo $row->titulo; ?>" >
<img src="<?php echo base_url(); ?>upload/image.php?imagen=<?php echo $fila['imagen1']; ?>" border="0"><br>
Enlarge Picture</a></div>

<?php } ?>

when i put this line somewhere after this code it picks up the whole link:
<meta property="og:image" content="<?php echo base_url(); ?>upload/gallery.php?imagen=<?php echo $fila['imagen1']; ?>"/>

but i need it to pick it up earlier in the code in the header

I know confusing especially since Im not revealing all code and the such

zerovic · 11-02-2015, 08:51 AM

did you solve the issue? if not, add me on skype (tamas.redler) or icq (320334087) and i'll help you fix this badboy ;)

tical · 11-02-2015, 08:54 AM

That's because $fila['imagen1'] is empty in some instances.

It works when you place it in the "...php if(!empty..." block because that code would only run when $fila['imagen1'] is not empty.

If you place your display code before the "...foreach ($data->result_array() as $fila)..." then it won't work because $fila hasn't been created yet.

SeanLEE · 11-02-2015, 09:00 AM

Quote:

Originally Posted by tical

That's because $fila['imagen1'] is empty in some instances.

It works when you place it in the "...php if(!empty..." block because that code would only run when $fila['imagen1'] is not empty.

If you place your display code before the "...foreach ($data->result_array() as $fila)..." then it won't work because $fila hasn't been created yet.

exactly... so can you write a line of code to fix this and ill pay you?

zerovic · 11-02-2015, 09:01 AM

Ok, so you posted this line, which doesn't seem to be working

Quote:

and what I see, is that the $fila['imagen1']; don't display anything.

I would like to ask you to add this under this meta property line

Quote:

<?php
if($_GET['dev']) {
print_r($fila);
}
?>

and call the same url adding ?dev=1 to the end of the url

So we can make sure the the array already exists! As you stated, that the code works below, I assume that the array is not created when you try to use it. To make it work, simply create the array before adding the meta property, so it will look like this

Quote:

<?php foreach ($data->result_array() as $fila) { ?>
<?php if (!empty($fila['imagen1'])) { ?>
<meta property="og:image" content="<?php echo base_url(); ?>upload/gallery.php?imagen=<?php echo $fila['imagen1']; ?>
<?php } } ?>

What it does, is basically creates the array based on $data->result_array(), and when $fila['imagen1'] is available, it will display the meta property.

Try it and let's see if it works out for you.

SeanLEE · 11-02-2015, 09:02 AM

Quote:

Originally Posted by zerovic

did you solve the issue? if not, add me on skype (tamas.redler) or icq (320334087) and i'll help you fix this badboy ;)

sent you a message on skype... help me out

SeanLEE · 11-02-2015, 10:18 AM

Quote:

Originally Posted by zerovic

Ok, so you posted this line, which doesn't seem to be working

and what I see, is that the $fila['imagen1']; don't display anything.

I would like to ask you to add this under this meta property line

and call the same url adding ?dev=1 to the end of the url

So we can make sure the the array already exists! As you stated, that the code works below, I assume that the array is not created when you try to use it. To make it work, simply create the array before adding the meta property, so it will look like this

What it does, is basically creates the array based on $data->result_array(), and when $fila['imagen1'] is available, it will display the meta property.

Try it and let's see if it works out for you.

Thanks for your work!!!! Job complete!~ Im VERY happy and I think I just found a new programmer for my team!!!!

Thanks Zerovic your the man!!!! (and you work super fast!)

11-02-2015, 08:28 AM	#2
2MuchMark Videochat Solutions Industry Role: Join Date: Aug 2004 Location: Canada Posts: 48,858	Try changing <meta property="og:image" content="<?php echo base_url(); ?>upload/gallery.php?imagen=<?php echo $fila['imagen1']; ?> to <meta property="og:image" content="<?php echo base_url(); ?>upload/gallery.php"?imagen="<?php echo $fila['imagen1']; ?>" __________________ Custom Coding \| Videochat Solutions \| Age Verification \| IT Help & Support www.2Much.net

11-02-2015, 08:34 AM	#4
sarettah see you later, I'm gone Industry Role: Join Date: Oct 2002 Posts: 14,078	There really is not enough code there to be sure what the issue is but my guess would be that instead of echo $fila['imagen1']; You should have echo $row->imagen1; or some such. (I say thatbecause fila means row. It looks like someone modified a script and maybe missed changing up a var to me. Without seeing what is in the database and what vars are coming from where all anyone can do is guess. . __________________ All cookies cleared!

11-02-2015, 08:51 AM	#7
zerovic Confirmed User Industry Role: Join Date: Apr 2010 Posts: 1,093	did you solve the issue? if not, add me on skype (tamas.redler) or icq (320334087) and i'll help you fix this badboy ;) __________________ php, html, jquery, javascript, wordpress - contact me at contact at zerovic.com

11-02-2015, 08:54 AM	#8
tical Confirmed User Join Date: Feb 2002 Location: Las Vegas Posts: 6,504	That's because $fila['imagen1'] is empty in some instances. It works when you place it in the "...php if(!empty..." block because that code would only run when $fila['imagen1'] is not empty. If you place your display code before the "...foreach ($data->result_array() as $fila)..." then it won't work because $fila hasn't been created yet. __________________ 112.020.756