Are there any mathematicians here? - GoFuckYourself.com

stocktrader23 · 11-01-2003, 04:01 PM

Is there anyone that could answer this for me?

Takes the numbers 1 - 14.

Now combine them in groups of 8 ie. 12345678, 12345679 etc.

How many seperate groups of numbers would there be with no 2 groupls containing the same set of 8 numbers?

Stud Money · 11-01-2003, 04:02 PM

JamesK · 11-01-2003, 04:02 PM

no way

BlueDesignStudios · 11-01-2003, 04:05 PM

Hrmmm......

stocktrader23 · 11-01-2003, 04:06 PM

It's not a test. I really need the answer.

testuser · 11-01-2003, 04:06 PM

If I read this right, that would be 14 choose 8.

Something like 14! / ( 8! 6!) = 3003.

Hindsight · 11-01-2003, 04:07 PM

i think the answer is 14 factorial but not definately sure

winter · 11-01-2003, 04:10 PM

Quote:

Originally posted by testuser
If I read this right, that would be 14 choose 8.

Something like 14! / ( 8! 6!) = 3003.

yup, this is correct:

http://www.google.com/search?sourcei...&q=14+choose+8

Poo-Chee · 11-01-2003, 04:24 PM

wtf ..

testuser · 11-01-2003, 04:34 PM

Whoa, I didn't know google had a calculator. And it does combinatorics? Sweet.

Quick explanation:
14! is the number of orderings of 14 distinct objects. Say you want to pick 8 out of 14 distinct objects. Then you have 14 ways to pick the first object, 13 ways to pick second object, ... , 7 ways to pick the 8th object = 14*13*...*7 = 14!/6!. But these are non-distinct groups, ie. some of the groups are just ordered in different ways. If you have 8 objects, you can order them in 8! different ways. So then you have 14!/(6!8!). Hope that was somewhat coherent.

fnet · 11-01-2003, 06:28 PM

do you mean 8 total digits or something weird like that?

Quote:

Originally posted by stocktrader23
Is there anyone that could answer this for me?

Takes the numbers 1 - 14.

Now combine them in groups of 8 ie. 12345678, 12345679 etc.

How many seperate groups of numbers would there be with no 2 groupls containing the same set of 8 numbers?

Poo-Chee · 11-01-2003, 06:41 PM

Quote:

Originally posted by fnet
do you mean 8 total digits or something weird like that?

it's been calculated already..

11-01-2003, 04:01 PM	#1
stocktrader23 Let's do some business. Industry Role: Join Date: Jan 2003 Location: The dirty south. Posts: 18,781	Are there any mathematicians here? Is there anyone that could answer this for me? Takes the numbers 1 - 14. Now combine them in groups of 8 ie. 12345678, 12345679 etc. How many seperate groups of numbers would there be with no 2 groupls containing the same set of 8 numbers? __________________ Hands Free Adult - Join Once, Earn For Life "I try to make a habit of bouncing my eyes up to the face of a beautiful woman, and often repeat “not mine” in my head or even verbally. She’s not mine. God has her set aside. She’s not mine. She’s His little girl, and she needs me to fight for her by keeping my eyes where they should be."

11-01-2003, 04:02 PM	#2
Stud Money So Fucking Banned Join Date: Sep 2003 Location: Somewhere between my monitor and my chair Posts: 3,214	WTF?

11-01-2003, 04:02 PM	#3
JamesK hi Industry Role: Join Date: Jun 2002 Posts: 16,731	no way __________________ M3Server - NATS Hosting

11-01-2003, 04:05 PM	#4
BlueDesignStudios Confirmed User Industry Role: Join Date: Feb 2003 Location: Australia Posts: 9,492	Hrmmm...... __________________ Blue Design Studios - Adult Design Specialists! Email me for a free quote: [email protected]

11-01-2003, 04:06 PM	#5
stocktrader23 Let's do some business. Industry Role: Join Date: Jan 2003 Location: The dirty south. Posts: 18,781	It's not a test. I really need the answer. __________________ Hands Free Adult - Join Once, Earn For Life "I try to make a habit of bouncing my eyes up to the face of a beautiful woman, and often repeat “not mine” in my head or even verbally. She’s not mine. God has her set aside. She’s not mine. She’s His little girl, and she needs me to fight for her by keeping my eyes where they should be."

11-01-2003, 04:06 PM	#6
testuser Registered User Join Date: Sep 2003 Posts: 95	If I read this right, that would be 14 choose 8. Something like 14! / ( 8! 6!) = 3003. __________________ ICQ: 273796889

11-01-2003, 04:07 PM	#7
Hindsight Confirmed User Join Date: Oct 2003 Location: Perugia, Italy - Often in Exeter, England Posts: 815	i think the answer is 14 factorial but not definately sure

11-01-2003, 04:24 PM	#9
Poo-Chee So Fucking Banned Join Date: Sep 2003 Location: Rotterdam Posts: 3,560	wtf ..

11-01-2003, 04:34 PM	#10
testuser Registered User Join Date: Sep 2003 Posts: 95	Whoa, I didn't know google had a calculator. And it does combinatorics? Sweet. Quick explanation: 14! is the number of orderings of 14 distinct objects. Say you want to pick 8 out of 14 distinct objects. Then you have 14 ways to pick the first object, 13 ways to pick second object, ... , 7 ways to pick the 8th object = 1413...*7 = 14!/6!. But these are non-distinct groups, ie. some of the groups are just ordered in different ways. If you have 8 objects, you can order them in 8! different ways. So then you have 14!/(6!8!). Hope that was somewhat coherent. __________________ ICQ: 273796889